updated for version 7.4.176v7.4.176

Problem:    Dictionary.update() thows an error when used without arguments.
            Python programmers don't expect that.
Solution:   Make Dictionary.update() without arguments do nothing. (ZyX)

1 files changed, 8 insertions, 2 deletions

diff --git a/src/if_py_both.h b/src/if_py_both.h
index 7c205f8c4f..9315324c46 100644
--- a/src/if_py_both.h
+++ b/src/if_py_both.h
@@ -1918,11 +1918,17 @@ DictionaryUpdate(DictionaryObject *self, PyObject *args, PyObject *kwargs)
     }
     else
     {
-	PyObject	*obj;
+	PyObject	*obj = NULL;
 
-	if (!PyArg_ParseTuple(args, "O", &obj))
+	if (!PyArg_ParseTuple(args, "|O", &obj))
 	    return NULL;
 
+	if (obj == NULL)
+	{
+	    Py_INCREF(Py_None);
+	    return Py_None;
+	}
+
 	if (PyObject_HasAttrString(obj, "keys"))
 	    return DictionaryUpdate(self, NULL, obj);
 	else