Use a clearer and shorter += or /= operation

Rewrite:

    i = i + 1

as

    i += 1

For a simple variable this is shorter, and a little bit clearer. For
more complex expressions it avoids making the reader having to
visually check that the left and right hand side of the assignment
really do have the same expression and that nothing tricky is going
on.

This was found by the clippy lint assign_op_pattern:
https://rust-lang.github.io/rust-clippy/master/index.html#assign_op_pattern

1 files changed, 1 insertions, 1 deletions

diff --git a/buffered-reader/src/lib.rs b/buffered-reader/src/lib.rs
index 918b7268..1ee7514b 100644
--- a/buffered-reader/src/lib.rs
+++ b/buffered-reader/src/lib.rs
@@ -834,7 +834,7 @@ pub trait BufferedReader<C> : io::Read + fmt::Debug + fmt::Display + Send + Sync
                 writeln!(sink, "  {}. {}, {:?}", i, r, cookie)?;
             }
             reader = r.get_ref();
-            i = i + 1;
+            i += 1;
         }
         Ok(())
     }