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When converting binary values to Base 64 encoding, we go from a 8 bit
representation to a 6 bit representation. As a result, we need extra space
to store the result compared to the input value being converted.
In the current implementation, the requirements on the size of the output
buffer are too conservative; We only have to check if the remaining space
is larger than 4 (3 input bytes get converted into 4 Base64 encoded output
bytes, plus allowing for a terminating '\0' character) rather than 10.
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Use mutt_buffer_len() and mutt_buffer_clear() to make the code a bit
clearer. There are still places in the code that manipulate the
buffers directly (pattern.c, for example), but that doesn't mean we
shouldn't abstract the buffer where we can.
Add comments in a couple places where unusual buffer manipulation is
occurring.
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Add mutt_buffer_from_base64() mutt_buffer_to_base64() to help with
transitioning to buffers.
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The result of
find . -name "*.[ch]" -exec emacs -batch {} \
--eval="(progn (delete-trailing-whitespace) (and (buffer-modified-p) (save-buffer)))" \;
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The obuf can be overflowed in auth_cram.c, and possibly auth_gss.c.
Thanks to Jeriko One for the bug report.
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Remove it from mutt.h
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